Carbon dioxide is passed into an excess of calcium hydroxide solution. Determine the volume of CO2

Carbon dioxide is passed into an excess of calcium hydroxide solution. Determine the volume of CO2 that must be passed into the solution to obtain 150 g of sediment.

1. We compose the reaction equation:

Ca (OH) 2 + CO2 = CaCO3 + H2O

The precipitate is calcium carbonate – CaCO3.

According to the equation: 1 mol of CaCO3 was formed. Let’s find its mass by the formula: m = n * M

m (CaCO3) = 1 mol * (40 + 12 + 16 * 3) = 100 g

According to the equation: 1 mol of CO2 entered the reaction, i.e. 22.4 l

2. We calculate the volume of carbon dioxide, making up the proportion:

150 g CaCO3 – xl CO2

100 g CaCO3 – 22.4 l CO2

Hence, x = 150 * 22.4 / 100 = 33.6 liters.