Carbon dioxide is produced by the interaction of calcium carbotane with hydrochloric acid.

Carbon dioxide is produced by the interaction of calcium carbotane with hydrochloric acid. The reaction product yield is 90%. Calculate how much carbon dioxide will be obtained from calcium carbotane weighing 20 g.

Given:
η (CO2) = 90%
m (CaCO3) = 20 g

To find:
V practical. (CO2) -?

Decision:
1) CaCO3 + 2HCl => CaCl2 + CO2 ↑ + H2O;
2) M (CaCO3) = Mr (CaCO3) = Ar (Ca) * N (Ca) + Ar (C) * N (C) + Ar (O) * N (O) = 40 * 1 + 12 * 1 + 16 * 3 = 100 g / mol;
3) n (CaCO3) = m (CaCO3) / M (CaCO3) = 20/100 = 0.2 mol;
4) n theory. (CO2) = n (CaCO3) = 0.2 mol;
5) V theor. (CO2) = n theory. (CO2) * Vm = 0.2 * 22.4 = 4.48 l;
6) V practical. (CO2) = η (CO2) * V theor. (CO2) / 100% = 90% * 4.48 / 100% = 4 liters.

Answer: The practical CO2 volume is 4 liters.



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