Carbon dioxide was passed through 40 g of a solution with a mass fraction of sodium hydroxide of 6%

Carbon dioxide was passed through 40 g of a solution with a mass fraction of sodium hydroxide of 6% until sodium carbonate was formed. Calculate the volume of gas consumed in the reaction.

Let’s write the reaction equation:

2NaOH + CO2 = Na2CO3 + H2O

Find the mass of sodium hydroxide:

m (NaOH) = mr.-pa (NaOH) * w (NaOH) / 100 = 40 * 6/100 = 2.4 (g).

Let’s find the amount of sodium hydroxide substance:

v (NaOH) = m (NaOH) / M (NaOH) = 2.4 / 40 = 0.06 (mol).

According to the reaction equation, 2 mol of NaOH reacts with 1 mol of CO2, therefore:

v (CO2) = v (NaOH) / 2 = 0.06 / 2 = 0.03 (mol).

Thus, the volume of consumed carbon dioxide measured under normal conditions (n.u.):

V (CO2) = v (CO2) * Vm = 0.03 * 22.4 = 0.672 (L).

Answer: 0.672 l.