Carbon dioxide was passed through 40 g of the solution by mass fraction of sodium hydroxide of 6 percent

Carbon dioxide was passed through 40 g of the solution by mass fraction of sodium hydroxide of 6 percent until sodium carbonate was formed. Calculate the volume of gas consumed in the reaction.

Given:
m solution (NaOH) = 40 g
ω (NaOH) = 6%
Vm = 22.4 l / mol

To find:
V (CO2) -?

Decision:
1) 2NaOH + CO2 => Na2CO3 + H2O;
2) M (NaOH) = Mr (NaOH) = Ar (Na) * N (Na) + Ar (O) * N (O) + Ar (H) * N (H) = 23 * 1 + 16 * 1 + 1 * 1 = 40 g / mol;
3) m (NaOH) = ω (NaOH) * m solution (NaOH) / 100% = 6% * 40/100% = 2.4 g;
4) n (NaOH) = m (NaOH) / M (NaOH) = 2.4 / 40 = 0.06 mol;
5) n (CO2) = n (NaOH) / 2 = 0.06 / 2 = 0.03 mol;
6) V (CO2) = n (CO2) * Vm = 0.03 * 22.4 = 0.672 l.

Answer: The volume of CO2 is 0.672 liters.