Carbon dioxide was passed through 50 g of a solution with a mass fraction of calcium hydroxide of 20%

Carbon dioxide was passed through 50 g of a solution with a mass fraction of calcium hydroxide of 20% until calcium carbonate was formed. Calculate the volume of the reacted gas.

Given:
m solution (Ca (OH) 2) = 50 g
ω (Ca (OH) 2) = 20%

To find:
V (CO2) -?

Decision:
1) Ca (OH) 2 + CO2 => CaCO3 + H2O;
2) M (Ca (OH) 2) = Mr (Ca (OH) 2) = Ar (Ca) * N (Ca) + Ar (O) * N (O) + Ar (H) * N (H) = 40 * 1 + 16 * 2 + 1 * 2 = 74 g / mol;
3) m (Ca (OH) 2) = ω (Ca (OH) 2) * m solution (Ca (OH) 2) / 100% = 20% * 50/100% = 10 g;
4) n (Ca (OH) 2) = m (Ca (OH) 2) / M (Ca (OH) 2) = 10/74 = 0.14 mol;
5) n (CO2) = n (Ca (OH) 2) = 0.14 mol;
6) V (CO2) = n (CO2) * Vm = 0.14 * 22.4 = 3.136 l.

Answer: The CO2 volume is 3.136 liters.