Carbon dioxide was passed through a solution weighing 250 g with 10% sodium hydroxide. Determine the mass of carbon monoxide (V) reacted and the mass of the resulting average salt.
m solution (NaOH) = 250 g
ω (NaOH) = 10%
m (CO2) -?
m (salt) -?
1) 2NaOH + CO2 => Na2CO3 + H2O;
2) m (NaOH) = ω (NaOH) * m solution (NaOH) / 100% = 10% * 250/100% = 25 g;
3) n (NaOH) = m (NaOH) / M (NaOH) = 25/40 = 0.63 mol;
4) n (CO2) = n (NaOH) / 2 = 0.63 / 2 = 0.32 mol;
5) m (CO2) = n (CO2) * M (CO2) = 0.32 * 44 = 14.08 g;
6) n (Na2CO3) = n (NaOH) / 2 = 0.63 / 2 = 0.32 mol;
7) m (Na2CO3) = n (Na2CO3) * M (Na2CO3) = 0.32 * 106 = 33.92 g.
Answer: The mass of CO2 is 14.08 g; Na2CO3 – 33.92 g.
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