Carbon dioxide was passed through a solution weighing 250 g with a mass fraction

Carbon dioxide was passed through a solution weighing 250 g with a mass fraction of sodium hydroxide of 10%. Determine the mass of carbon monoxide (IV) reacted and the mass of the formed middle salt.

Given:
m solution (NaOH) = 250 g
ω (NaOH) = 10%

To find:
m (CO2) -?
m (salt) -?

Decision:
1) Write the reaction equation:
2NaOH + CO2 => Na2CO3 + H2O;
2) Calculate the mass of NaOH:
m (NaOH) = ω * m solution / 100% = 10% * 250/100% = 25 g;
3) Calculate the amount of NaOH substance:
n (NaOH) = m / M = 25/40 = 0.63 mol;
4) Determine the amount of substance CO2:
n (CO2) = n (NaOH) / 2 = 0.63 / 2 = 0.32 mol;
5) Calculate the mass of CO2:
m (CO2) = n * M = 0.32 * 44 = 14.08 g;
6) Calculate the amount of Na2CO3 substance:
n (Na2CO3) = n (NaOH) / 2 = 0.63 / 2 = 0.32 mol;
7) Calculate the mass of Na2CO3:
m (Na2CO3) = n * M = 0.32 * 106 = 33.92 g.

Answer: The mass of CO2 is 14.08 g; Na2CO3 – 33.92 g.