Carbon dioxide was passed through the calcium hydroxide solution. 648 g of a solution of calcium
Carbon dioxide was passed through the calcium hydroxide solution. 648 g of a solution of calcium bicarbonate with a mass fraction of 1% were formed. Calculate the volume of the reacted gas
Given:
m solution (Ca (HCO3) 2) = 648 g
ω (Ca (HCO3) 2) = 1%
To find:
V (gas) -?
Decision:
1) Ca (OH) 2 + 2CO2 => Ca (HCO3) 2;
2) M (Ca (HCO3) 2) = Mr (Ca (HCO3) 2) = Ar (Ca) * N (Ca) + Ar (H) * N (H) + Ar (C) * N (C) + Ar (O) * N (O) = 40 * 1 + 1 * 2 + 1 * 2 + 16 * 3 * 2 = 162 g / mol;
3) m (Ca (HCO3) 2) = ω (Ca (HCO3) 2) * m solution (Ca (HCO3) 2) / 100% = 1% * 648/100% = 6.48 g;
4) n (Ca (HCO3) 2) = m (Ca (HCO3) 2) / M (Ca (HCO3) 2) = 6.48 / 162 = 0.04 mol;
5) n (CO2) = n (Ca (HCO3) 2) * 2 = 0.04 * 2 = 0.08 mol;
6) V (CO2) = n (CO2) * Vm = 0.08 * 22.4 = 1.792 l.
Answer: The volume of CO2 is 1,792 liters.