Carbon dioxide was passed through the calcium hydroxide solution. Formed 324 g of a solution of calcium

Carbon dioxide was passed through the calcium hydroxide solution. Formed 324 g of a solution of calcium bicarbonate with a mass fraction of 1%. Calculate the volume of the reactant gas

Given:
m solution (Ca (HCO3) 2) = 324 g
ω (Ca (HCO3) 2) = 1%

To find:
V (gas) -?

Decision:
1) Ca (OH) 2 + 2CO2 => Ca (HCO3) 2;
2) M (Ca (HCO3) 2) = Mr (Ca (HCO3) 2) = Ar (Ca) * N (Ca) + Ar (H) * N (H) + Ar (C) * N (C) + Ar (O) * N (O) = 40 * 1 + 1 * 2 + 1 * 2 + 16 * 3 * 2 = 162 g / mol;
3) m (Ca (HCO3) 2) = ω (Ca (HCO3) 2) * m solution (Ca (HCO3) 2) / 100% = 1% * 324/100% = 3.24 g;
4) n (Ca (HCO3) 2) = m (Ca (HCO3) 2) / M (Ca (HCO3) 2) = 3.24 / 162 = 0.02 mol;
5) n (CO2) = n (Ca (HCO3) 2) * 2 = 0.02 * 2 = 0.04 mol;
6) V (CO2) = n (CO2) * Vm = 0.04 * 22.4 = 0.896 l.

Answer: The volume of CO2 is 0.896 liters.