Carbon dioxide was passed through the lime water. as a result, an acidic salt was formed and 6 g of precipitate fell out.

Carbon dioxide was passed through the lime water. as a result, an acidic salt was formed and 6 g of precipitate fell out. after prolonged boiling of the solution, the mass of the sediment increased by 2 g. a) Determine the volume of carbon dioxide absorbed by lime water. b) Calculate the volume of carbon dioxide that will be released during the complete decomposition of the sediment obtained as a result of the described experiment.

Given:
m1 (sediment) = 6 g
Δm (sediment) = 2 g

To find:
V react. (CO2) -?
V release (CO2) -?

Decision:
1) Ca (OH) 2 + 2CO2 => Ca (HCO3) 2;
Ca (OH) 2 + CO2 => CaCO3 ↓ + H2O;
Ca (HCO3) 2 = (toC) => CaCO3 ↓ + CO2 ↑ + H2O;
2) n1 (CaCO3) = m1 (CaCO3) / M (CaCO3) = 6/100 = 0.06 mol;
3) n2 (CO2) = n1 (CaCO3) = 0.06 mol;
4) m2 (CaCO3) = Δm (sediment) = 2 g;
5) n2 (CaCO3) = m2 (CaCO3) / M (CaCO3) = 2/100 = 0.02 mol;
6) n (Ca (HCO3) 2) = n2 (CaCO3) = 0.02 mol;
7) n1 (CO2) = n (Ca (HCO3) 2) * 2 = 0.02 * 2 = 0.04 mol;
8) n react. (CO2) = n1 (CO2) + n2 (CO2) = 0.04 + 0.06 = 0.1 mol;
9) V react. (CO2) = n react. (CO2) * Vm = 0.1 * 22.4 = 2.24 L;
10) n issue. (CO2) = n2 (CaCO3) = 0.02 mol;
11) V issue. (CO2) = n out. (CO2) * Vm = 0.02 * 22.4 = 0.448 l.

Answer: The volume of absorbed CO2 is 2.24 liters; released – 0.448 liters.