Carbon dioxide with a mass of 0.02 kg is heated at a constant volume. Determine the change in the internal energy

Carbon dioxide with a mass of 0.02 kg is heated at a constant volume. Determine the change in the internal energy of the gas when heated from 20 ° C to 108 ° C (C = 655 J / kg * K)

Given: m (mass of carbon dioxide) = 0.02 kg; t1 (initial gas temperature) = 20 ºС; t2 (final temperature) = 108 ºС; V (volume) = const.

Constants: by condition C (specific heat of carbon dioxide) = 655 J / (kg * K).

Solution: To calculate the change (increase) in the internal energy of taken carbon dioxide, we apply the formula: ΔU = Q (isochoric process) = C * m * (t2 – t1) = 655 * 0.02 * (108 – 20) = 1152.8 J …

Answer: The internal energy of the taken carbon dioxide should have increased by 1152.8 J.