Carbon dioxide with a volume of 11.2 liters is introduced into water, 0.55 mol of barium hydroxide

| June 21, 2021 | education

Carbon dioxide with a volume of 11.2 liters is introduced into water, 0.55 mol of barium hydroxide is added and a precipitate is obtained with a mass

Chemical reaction equation:
0.55 mol 0.5 mol 0.5 mol
Ba (OH) 2 + CO2 + H2O = BaCO3 ↓ + 2H2O
1 mol 1 mol 1 mol
The amount of CO2 substance that reacts,
n (CO2) = V (CO2) / Vm = 11.2 l / 22.4 l / mol = 0.5 mol.
According to the reaction equation, Ba (OH) 2 and CO2 react in a 1: 1 ratio. Therefore, barium hydroxide is taken in excess (0.55 mol> 0.5 mol). The calculation of the amount of the substance BaCO3 is carried out according to the lack.
n (ВаСО3) = n (СО2) = 0.5 mol.
Barium carbonate mass: m (ВаСО3) = n (ВаСО3) * M (ВаСО3) = 0.5 mol * 197 g / mol = 98.5 g,
where M (ВаСО3) is the molar mass of ВаСО3.



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