Carry out the following transformations: Al4C3-CH4-CH3Cl-C2H6

1) Al4C3 + 12H2O = 3CH4 + 4Al (OH) 3 – exchange reaction; methane is formed.
2) CH4 + Cl2 = CH3Cl + HCl – substitution reaction, halogenation; chloromethane is formed.
3) 2CH3Cl + 2Na = C2H6 + 2NaCl – Wurtz reaction, interaction of sodium with halogenated alkanes; ethane is formed.



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