Carry out the following transformations: ammonium methane-hydrogen sulfate phenyl.

Carry out the following transformations: ammonium methane-hydrogen sulfate phenyl. To neutralize 10 g of a mixture of aniline and phenol, 49.02 ml of a solution with a mass fraction of potassium hydroxide equal to 2.24% and a density of 1.02 g / ml were required when an excess of bromine water was added to 10 g of the same mixture, 16.52 g of precipitate was obtained. Determine the masses of aniline and phenol in the initial mixture.

1. Reaction between phenol and bromine water:
С6Н5ОН + 3Br2 = С6H2Br3OH + 3НBr
Reaction between aniline and bromine water
C6H5NH2 + 3Br2 -> C6H2NH2Br3 + 3HBr
2. Neutralization of phenol:
C6H5OH + KOH → C6H5OK + H2O
Alkali solution mass:
m = ρ * V = 1.02 * 49.02 = 50 g
Alkali solution mass:
m (KOH) = m * w / 100 = 50 * 2.24 / 100 = 1.12g
Alkali amount:
n (KOH) = 1.12 / 56 = 0.02 mol
According to the equation, the amount of acid is equal to the amount of alkali:
n (С6Н5ОН) = n (КOH) = 0.02 mol
Acid mass:
m (C6H5OH) = n (C6H5OH) * M (C6H5OH) = 0.02 * 94 = 1.88 g
Aniline mass:
m (C6H5NH2) = mc-m (C6H5OH) = 10-1.88 = 8.12 g.
Answer: the mass of aniline is 8.12 g, the mass of phenol is 1.88 g