Chemistry 80 grams of water was added to 80 grams of 5% salt solution.

Chemistry 80 grams of water was added to 80 grams of 5% salt solution. How much solution and what concentration was formed?

We have a 5% salt solution and an additional 80 g of water.
To begin with, we find exactly how much pure salt (its mass) is in the solution:
m1 = 80 * 0.05 = 4 grams of pure salt.
Next, you need to find the mass of the solvent, that is, water, by subtracting the mass of pure salt from the mass of the solution (calculation above).
m2 of water = 80 – 4 = 76 grams.
To find a new concentration, you need to make up the proportion:
w2 = m1 / (m1 + m2 + 80)
w2 = 4 / (4 + 76 + 80) = 0.025 = 2.5%
Answer: the new concentration of the solution is 2.5%