Chemistry, please urgently Calculate the mass of a 12 percent barium hydroxide solution required

| July 22, 2021 | education

Chemistry, please urgently Calculate the mass of a 12 percent barium hydroxide solution required to react with 26.7 g of aluminum chloride.

Answer: m (solution) = 427.5 g.
Explanation of the solution to the problem: to solve this problem, you first need to write the equation of the chemical reaction: 3Ba (OH) 2 (dil.) + 2AlCl3 => 3BaCl2 + 2Al (OH) 3 ↓
then you need to find the amount of aluminum chloride substance, for this you need to use the following formula:
n (AlCl3) = m / M = 26.7 / 133.5 = 0.2 mol mol.
According to the reaction equation, it can be seen that the amount of barium hydroxide substance is equal to:
n (Ba (OH) 2) = 3 * n (AlCl3) / 2 = 0.3 mol.
Now we find the mass, for this we multiply the found amount of the substance by its molar mass:
m (Ba (OH) 2) = n (Ba (OH) 2) * M = 0.3 * 171 = 51.3 g.
The last step is to find the mass of the solution by the formula:
w = m (solv.v-va) / m (solution), where w is the mass fraction of the solute in the solution, m (solv.v-va) is the mass of the solute, m (solution) is the mass of the solution …
m (solution) = m (solution in-va) / w = 51.3 / 0.12 = 427.5 g.



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