Chlorination of 160 g of methane gave chloromethane in 85% yield. Find the mass of the resulting substance

univerkov | December 7, 2020 | education

Given:
m (CH4) -160g
w (CH3CI) -85%
Find: mv-v
Decision:
We write the reaction equation: 1) CH4 + CI = CH3CI + HCI
n (CH4) = m / M = 160/16 = 10 = 0.1 mol
M (CH4) = 12 + 1 * 4 = 16
2) n (CH4) = n (CH3CI)
3) m (CH3CI) -n * M = 0.1 * 50.5 = 5.05
M (CH3CI) = 12 + 1 * 3 + 35.5 = 50.5
m (CH3CI) = 5.05 * 0.85 = 4.3g
Answer: 4.3g

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