Chlorine was passed through an excess of potassium iodide solution. Determines the amount

Chlorine was passed through an excess of potassium iodide solution. Determines the amount of chlorine required to obtain 34 g of iodine.

Given:
m (I2) = 34 g
Vm = 22.4 l / mol

To find:
V (Cl2) -?

Decision:
1) Write the equation of a chemical reaction:
Cl2 + 2KI => 2KCl + I2;
2) Calculate the molar mass of iodine:
M (I2) = Mr (I2) = Ar (I) * N (I) = 127 * 2 = 254 g / mol;
3) Calculate the amount of iodine substance:
n (I2) = m (I2) / M (I2) = 34/254 = 0.13 mol;
4) Determine the amount of chlorine substance:
n (Cl2) = n (I2) = 0.13 mol;
5) Calculate the volume of chlorine:
V (Cl2) = n (Cl2) * Vm = 0.13 * 22.4 = 2.9 liters.

Answer: The volume of Cl2 is 2.9 liters.