Chloroacetic acid was obtained from 30 g of acetic acid with a practical yield of 60%

| September 26, 2021 | education

Chloroacetic acid was obtained from 30 g of acetic acid with a practical yield of 60%, ammonia with a volume of 72 liters was passed through this acid. Calculate the amount of aminoacetic acid substance.

To solve, we compose the equations:
m = 30 g. W = 60%
1. CH3COOH + Cl2 = CH2 (Cl) – COOH + HCl – substitution, chloroacetic acid is released;
V = 72 HP Y mole -?
2. CH2 (Cl) – COOH + NH3 = CH2 (NH2) – COOH + NH4Cl – exchange, aminoacetic acid was obtained;
3. Calculations:
M (CH3COOH) = 60 g / mol;
M (chloroacetic acid) = 62.5 g / mol;
Y (CH3COOH) = m / M = 30/60 = 0.5 mol.
4. Determine the mass, the amount of chloroacetic acid:
m (theoretical) = Y * M = 0.5 * 62.5 = 31.25 g;
m (practical) = Y * M = 0.60 * 31.25 = 18.75 g;
Y = m / M = 18.75 / 62.5 = 0.3 mol.
5. Y (aminoox. To-you) = 0.3 mol, since the amount of substances according to the equation is 1 mol.
Answer: Aminoacetic acid was obtained in the amount of 0.3 mol.



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