Chloroacetic acid was obtained from acetic acid, weighing 27 g.

Chloroacetic acid was obtained from acetic acid, weighing 27 g. Mass fraction of the product yield 60%. Determine the mass of the chloroacetic acid obtained.

The equation for the reaction of obtaining chloroacetic acid:

CH3COOH + Cl2 (t, cat.) = ClCH2COOH + HCl

The amount of acetic acid substance:

v (CH3COOH) = m (CH3COOH) / M (CH3COOH) = 27/60 = 0.45 (mol).

According to the reaction equation, from 1 mol of CH3COOH, 1 mol of ClCH2COOH is formed, therefore, taking into account the mass fraction of the yield of the reaction product:

v (ClCH2COOH) = v (CH3COOH) * 0.6 = 0.45 * 0.6 = 0.27 (mol).

Thus, the mass of the obtained chloroacetic acid:

m (ClCH2COOH) = v (ClCH2COOH) * M (ClCH2COOH) = 0.27 * 94.5 = 25.515 = 25.5 (g).