Chord AB divides the circle into two arcs. At what angle is the chord AB visible from the center

Chord AB divides the circle into two arcs. At what angle is the chord AB visible from the center of the circle, if the ratio of the magnitudes of the arcs is: 7:11.

Let the degree measure of the smaller arc AB = 7 * X0, then by condition, the degree measure of the larger arc AB = 11 * X0.

The degree measure of the circle is 3600, then 7 * X + 11 * X = 360.

18 * X = 360.

X = 360/18 = 20.

Then the degree measure of the smaller arc AB = 7 * 20 = 140.

The degree measure of the central angle AOB, based on the smaller arc AB, is equal to the degree measure of this arc, then the angle AOB = 140.

Answer: From the center of the circle, the sludge AB is seen at an angle of 140.