Chord AB is equal to half the diameter of AC. Find corner C.

univerkov | December 29, 2020 | education

Connect point B of the chord and point C of the diameter of the circle. The formed triangle ABC is rectangular, with a right angle at point B, since it rests on the diameter of the circle.
By condition, the chord AB is equal to half the diameter of the AC. AB = AC / 2. AC = 2 * AB.
Then SinACB = AB / AC = AB / 2 * AB = 1/2.
Angle ACB = arcsin (1/2) = 300.
Answer: The ACB angle is 300.

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