Chord CD intersects diameter AB at point K find the segments into which point K divides the diameter

Chord CD intersects diameter AB at point K find the segments into which point K divides the diameter if the radius of the circle is 6 cm CK = 4 cm DK = 5 cm

diameter = 2r = 12cm
by terroem about intersecting chords (diameter is the same chord)
CK * DK = AK * BK
Let AK be x cm, and ВK 12 – x. make an equation
4 * 5 = x (12-x)
12x-x ^ 2 = 20
x ^ 2-12x + 20 = 0
D = 144-80 = 64
x1 = 12 + 8/2 = 10 cm = AK1
x2 = 12-8 / 2 = 2 cm = AK2
i.e. two answers will be obtained
BK1 = 12-10 = 2 cm
BK2 = 12-2 = 10 cm
Answer10 and 2 cm, 2 and 10 cm