Chords AB and CD intersect at point E. Find AB if CE = 8cm; ED = 20mm; BE = 4.2cm.

Since the chords AB and CD intersect at the point E, then by the property of intersecting chords, the product of the lengths of the segments of one chord is equal to the product of the lengths of the segments of the other chord.

AE * BE = CE * DE.

AE = CE * DE / BE = 8 * 20 / 4.2 = 160 / 4.2 = 38.1 cm

Then AB = AE + BE = 38.1 + 4.2 = 42.3 cm.

Answer: The length of the chord AB is 42.3 m.



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