Chords AB and CD meet at point E, AE = 3, BE = 12. Find: CE = DE

Let the length of the segment CE = X cm, then the length of the segment DE = X cm.

By the property of intersecting chords, the product of the lengths of the segments of one chord is equal to the product of the lengths of the segments of the other chord.

AE * BE = CE * DE.

3 * 12 = X * X.

X2 = 36.

X = 6 cm.

CE = DE = 6 cm.

Answer: The length of the segments CE and DE is 6 cm.



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