Chords AB and CD meet at point E. Find CD if AE = 4.6 cm; BE = 12mm; ED = 10cm.

univerkov | September 17, 2021 | education

By the property of intersecting chords, the product of the segments formed at the intersection of one chord is equal to the product of the lengths of the segments of the other chord.

AE * BE = CE * DE.

CE = AE * BE / DE = 4.6 * 12/10 = 5.52 cm.

Then CD = DE + CE = 10 + 5.53 = 15.52 cm.

Answer: The length of the CD chord is 15.52 cm.

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