CM – perpendicular to the plane of the square ABCD. Find the distance from point M to lines AB

CM – perpendicular to the plane of the square ABCD. Find the distance from point M to lines AB and CB, if AD = 2 cm, MB = 5 cm.

Determine the distance from point M to line AB.

The segment MB is perpendicular to AB, therefore this is the distance from point M to the side of the square AB.

MB = 5 cm.

Determine the distance from point M to the segment CB.

The MC segment is perpendicular to the BC side, then the BCM triangle is rectangular. By the Pythagorean theorem, we determine the length of the MC leg.

MC ^ 2 = MB ^ 2 – BC ^ 2 = 5 ^ 2 – BC ^ 2 = 25 – 4 = 21.

MC = √21 cm2.

Answer: The distance from M to AB is 5 cm, the distance from M to BC is √21 cm2.



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