Compare the acceleration of the second and minute hands of the same length.

The extreme points of both arrows are spaced from the axis of rotation at the same distance R and move at a constant speed. This means that centripetal acceleration acts on them, which can be determined by the formula: a = (v ^ 2): R. But v = (2 ∙ π ∙ R): T, where 2 ∙ π ∙ R is the path traversed by the end of the arrow along dial, T – time of one complete revolution of the hand or period of rotation. For the second hand T1 = 60 s, for the minute hand T2 = 3600 s. Then a1: a2 = (T2: T1) ^ 2 or a1: a2 = (3600: 60) ^ 2; a1: a2 = 3600 (times)
Answer: the acceleration of the second hand is 3600 times greater.