Compare the areas of two rectangles, if the first rectangle has a length of 5 dm

| May 9, 2021 | education

Compare the areas of two rectangles, if the first rectangle has a length of 5 dm, a width of 3 dm, the second has a length of 7 dm, a width of 2 dm.

To solve this problem, recall the formula for the area of a rectangle. The area of the rectangle is equal to the product of the length and the width. S = a * b, where a is the length and b is the width. Let’s calculate the area of the first rectangle, knowing that its length is 5 dm, and its width is 3 dm.
S1 = a * b = 5 * 3 = 15 dm ^ 2.
Let’s calculate the area of the second rectangle, knowing that its length is 7 dm, and its width is 2 dm.
S2 = a * b = 7 * 2 = 14 dm ^ 2.
Let’s compare the areas.
15 dm ^ 2> 14 dm ^ 2.
15-14 = 1 dm ^ 2.
Answer: the area of the first rectangle is 1 dm ^ 2 larger than the area of the second rectangle.



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