Compare the paths that carts with masses of 2 and 5 kg travel in the first two seconds under the action

Compare the paths that carts with masses of 2 and 5 kg travel in the first two seconds under the action of a force of 10 and 20 Newtons, respectively, take the initial speed of the carts equal to zero, neglect friction.

To compare the speeds of the bogies under consideration, we use the relation: k = V1 / V2 = a1 * t / (a2 * t) = (F1 / m1) / (F2 / m2) = F1 * m2 / (F2 * m1).
Values of variables: F1 – force acting on the first carriage (F1 = 10 N); m2 is the mass of the second cart (m2 = 5 kg); F2 – force acting on the second carriage (F2 = 20 N); m1 is the mass of the first bogie under consideration (m1 = 2 kg).
Let’s perform the calculation: k = 10 * 5 / (20 * 2) = 1.25 p.
Answer: The first cart should travel 1.25 times longer.