Compare the surface areas of a cube and a rectangular parallelepiped, if the edge of the cube is 10 dm, and the dimensions

| April 23, 2021 | education

Compare the surface areas of a cube and a rectangular parallelepiped, if the edge of the cube is 10 dm, and the dimensions of the rectangular parallelepiped are 4 m, 25 dm, 70 cm.

The cube and the parallelepiped have 6 faces, only the cube has all the same faces and their area is equal to the edge of the cube multiplied by 6.

Let us find the surface area of a cube with an edge equal to 10 dm.

S = 6 * (10 dm) ² = 600 dm².

Let’s find the surface area of a rectangular parallelepiped with measurements of 4 m, 25 dm, 70 cm.

Let’s convert all measurements to decimeters. 4 m = 40 dm, 70 cm = 0.7 dm.

S = (40 dm * 25 dm + 40 dm * 0.7 dm + 25 dm * 0.7 dm) * 2 = 2091 dm².

Let’s compare the areas.

2091 dm² – 600 dm² = 1491 dm².

Answer: the surface area of the parallelepiped is 1491 dm² larger.



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