Compare the work performed by a person by stretching the dynamometer spring from 0 to 10 N, from 10 to 20 N, from 20 to 30 N.

Work is a physical quantity that is numerically equal to the product of the modulus of the force acting on the body by the modulus of displacement that the body performs under the action of this force, and by the cosine of the angle between the direction of the force and the direction of motion of the body:
A = F * S * cos α
Our work is equal to:
A = k (x2²-x1²) / 2
Hooke’s Law: The elastic force is directly proportional to the amount of deformation.
Fпр = k * x, where k is a coefficient showing the stiffness of the spring, x is the change in body length.
x = Fcont / k = F / k (Fcont = F)
A1 = k (F1²-F0²) / 2k² = (F1²-F0²) / 2k
A2 = k (F2²-F1²) / 2k² = (F2²-F1²) / 2k
A3 = k (F3²-F2²) / 2k² = (F3²-F2²) / 2k
A2 / A1 = ((F2²-F1²) / 2k) / ((F1²-F0²) / 2k) = F2²-F1² / (F1²-F0²) = 20²-10² / 10² = 3
A3 / A1 = ((F3²-F2²) / 2k) / ((F1²-F0²) / 2k) = F3²-F2² / (F1²-F0²) = 30²-20² / 10² = 5
A3 / A2 = ((F3²-F2²) / 2k) / ((F2²-F1²) / 2k) = F3²-F2² / (F2²-F1²) = 30²-20² / 20² = 1.66
Answer: works A1: A2: A3 are related as 1: 3: 5.