Computationally, what volume of carbon dioxide can be obtained by calcining 10.92 g of sodium

Computationally, what volume of carbon dioxide can be obtained by calcining 10.92 g of sodium bicarbonate, if the yield of the reaction product is 92% of the theoretical.

The decomposition reaction of sodium bicarbonate is described by the following chemical reaction equation:

NaHCO3 = NaO + CO2 + H2O;

The decomposition of 1 mol of sodium bicarbonate synthesizes 1 mol of gaseous carbon dioxide.

Let’s calculate the available chemical amount of sodium bicarbonate substance.

M NaHCO3 = 23 + 1 + 12 + 16 x 3 = 84 grams / mol;

N NaHCO3 = 10.92 / 84 = 0.13 mol;

Taking into account the reaction yield of 92%, 0.13 x 0.92 = 0.12 mol of carbon dioxide will be synthesized.

Let’s calculate the volume of carbon dioxide. To do this, multiply the amount of the substance and the standard volume of 1 mole of the gaseous substance. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V CO2 = 0.12 x 22.4 = 2.688 liters;