Conductors with a resistance of 2 ohms, 4 ohms and 6 ohms are connected in series and connected to a network

Conductors with a resistance of 2 ohms, 4 ohms and 6 ohms are connected in series and connected to a network with a voltage of 36 V. What is the current in the conductors?

First, we find the total resistance Rtot, since the connection of the conductors is serial, then we simply add up the reading from each conductor.
R1 + R2 + R3 = Rtot
Rtot = 2 + 4 + 6 = 12 Ohm
Further, everything is according to Ohm’s law I = U ÷ R
We substitute everything into the formula: I = 36 ÷ 12 = 3 A
Answer: 3 A