Conductors with a resistance of 2 ohms and 6 ohms are connected in series and connected to a network

Conductors with a resistance of 2 ohms and 6 ohms are connected in series and connected to a network with a voltage of 36V. Calculate the amperage in the conductor.

Given:

R1 = 2 Ohm – resistance of the first conductor;

R2 = 6 Ohm – resistance of the second conductor;

U = 36 Volts – mains voltage.

It is required to determine the current in the circuit I (Ampere).

Since, according to the condition of the problem, the conductors are connected in series, we will find the total resistance of the circuit section:

R = R1 + R2 = 2 + 6 = 8 ohms.

Then, according to Ohm’s law, the current strength will be:

I = U / R = 36/8 = 4.5 Amperes.

Answer: the current in the conductor will be 4.5 Amperes.