Consider the recorded reaction in terms of redox processes. Zn + 2HCl = ZnCl2 + H2

First, we write down the equation of the corresponding chemical reaction.
Zn + 2HCl = ZnCl2 + H2.
This reaction involves zinc, Zn, and hydrogen chloride or hydrogen chloride, that is, HCl. As a result of this reaction, zinc chloride, ZnCl2, as well as hydrogen, H2 are formed.
Now consider the above reaction from the point of view of oxidation-reduction processes. In this case, we draw attention to the fact that redox reactions are such reactions as a result of which there is a change in the oxidation states of the corresponding atoms of the reacting substances. That is, in this case, a redistribution of electrons occurs between the reducing atom and the oxidizing atom.
1.) As a result of this reaction, Zn (0) donates electrons and is oxidized.
Zn – 2e = Zn (+2).
Thus, zinc gives up two electrons, while an increase in the oxidation state of zinc occurs, that is, Zn is a reducing agent.
2.) Now let’s look at what happens to hydrogen, that is, to H2.
Hydrogen ions, accepting electrons, are reduced to a free state.
2H (+) + 2e = H2.
Thus, hydrogen accepts two electrons, while its oxidation state decreases, that is, H2 is an oxidizing agent.