Considering that each character is encoded by 1 byte, determine: the information volume of one page of the textbook
| December 5, 2020 | education
Considering that each character is encoded by 1 byte, determine: the information volume of one page of the textbook, if it has 32 lines and 58 characters (per line) – how many pages of the textbook will fit in a computer with 300MB of memory
1) 58 * 32 = 1856 Bytes
2) 300 MB = 300 * 1024 KB = 307200 * 1024 Bytes 314572800 Bytes
314572800/1856 = 169489 pages
Answer: 169489 pages
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