Considering the Earth a satellite of the Sun, calculate the speed of the Earth’s orbital motion
Considering the Earth a satellite of the Sun, calculate the speed of the Earth’s orbital motion, the radius of the Earth’s orbit = 150,000,000 km, the mass of the Sun = 2 * 10 ^ 10
To find the required speed of the Earth’s orbital motion, we use the equality: G * Ms * Mc / R ^ 2 = F = Ms * ac = Ms * V2 / R, from where we express: V = √ (G * Mc / R).
Constants and variables: G – gravitational constant (G = 6.72 * 10 ^ -11 N * m2 / kg); Mc is the mass of the Sun (Mc = 2 * 10 ^ 30 kg); R is the radius of the Earth’s orbit (R = 150 * 10 ^ 6 km = 150 * 10 ^ 9 m).
Let’s calculate: V = √ (G * Mc / R) = √ (6.72 * 10 ^ -11 * 2 * 10 ^ 30 / (150 * 10 ^ 9)) = 29933 m / s ≈ 29.9 km / from.
Answer: The speed of the Earth’s orbital motion, according to the calculation, is 29.9 km / s.