Considering the mass of the sun equal to 2 * 10 ^ 27t, determine the acceleration of gravity

Considering the mass of the sun equal to 2 * 10 ^ 27t, determine the acceleration of gravity at a distance of 7 * 10 ^ 8m from the center of the sun.

Data: according to the condition M (mass of the Sun) = 2 * 10 ^ 27 t; R (distance from the center of the Sun, radius of the Sun) = 7 * 10 ^ 8 m; G (gravitational constant) = 6.67 * 10 ^ -11 m ^ 3 / (kg * s ^ 2).

SI system: M = 2 * 10 ^ 27 t = 2 * 10 ^ 30 kg.

Free fall acceleration at a distance of 7 * 10 ^ 8 m from the center of the Sun: g = G * M / R ^ 2.

Let’s do the calculation:

g = 6.67 * 10 ^ -11 * 2 * 10 ^ 30 / (7 * 10 ^ 8) ^ 2 = 272.2 m / s ^ 2.

Answer: According to the calculation, the acceleration of gravity at a distance of 7 * 10 ^ 8 m from the center of the Sun is 272.2 m / s ^ 2.