Construct a rectangle, the width of which is 4 cm, and the length is 2 times longer, we calculated its perimeter and area.

We are given a rectangle that is 4 centimeters wide and twice its length. We need to find its area and perimeter, let’s start solving:

Since, by condition, we are given that the length is twice the width, then since the width is 4 centimeters, the length will be: 4 * 2 = 8 centimeters.

Since the length and width in a rectangle are equal to each other, denoting the length with the letter a, and the width with the letter b, then we can find the perimeter of this rectangle by the formula:

P = (a + b) * 2;

Now let’s substitute the values:

P = (4 + 8) * 2;

P = 24 centimeters;

The area is found by the formula S = a * b, substitute the values ​​and find the area:

S = 4 * 8 = 32 centimeters²

Answer: the perimeter of the rectangle is 24 centimeters, the area of ​​the rectangle is 32 centimeters²