Conversion of 200 g of water taken at temperature into steam, find the amount of heat required for the boiling

Conversion of 200 g of water taken at temperature into steam, find the amount of heat required for the boiling temperature, the specific heat of vaporization of water 2.3 multiplied by 10 to the 6th power of J / kg.

m = 200 grams = 0.2 kilograms is the mass of water heated to the boiling point;

q = 2.3 * 10 ^ 6 J / kg is the specific heat of vaporization of water.

It is required to determine Q (Joule) – the amount of heat required to turn water into steam.

Since, according to the condition of the problem, the water is already heated to the boiling point, that is, additional heating is not required, then:

Q = q * m = 0.2 * 2.3 * 10 ^ 6 = 0.46 * 10 ^ 6 Joules = 460 kJ.

Answer: to convert water into steam, it is necessary to expend energy equal to 460 kJ.