Convex quadrilateral ABCD has two pairs of equal between adjacent sides: AB = CD, BC = CD. О is the point
Convex quadrilateral ABCD has two pairs of equal between adjacent sides: AB = CD, BC = CD. О is the point of intersection of the diagonal of the quadrilaterals ABCOD and ABOCD. Compare the P (perimeter) of quads ABOCD and ABOCD.
Let’s write down the perimeters of the pentagons ABCOD and ABOCD.
P1 = AB + BC + OC + OD + AD.
P2 = AB + OB + OC + CD + AD.
By condition, the adjacent sides of the quadrilateral are equal, BC = CD, then:
P1 = (AB + BC + OC + AD) + OD.
P2 = (AB + BC + OC + AD) + OB.
The perimeters of the pentagons differ in the lengths ОВ and ОD.
A quadrangle with equal adjacent sides is a deltoid, or “kite”, in which the diagonals are perpendicular and one of them is divided in half, then OB = OD, and therefore P1 = P2.
Answer: The perimeters are equal.