Copper oxide +2 weighing 40 g reacts with hydrogen. Find the mass of the formed water.

Divalent copper oxide is reduced with hydrogen gas when heated. This synthesizes metallic copper and water. The reaction is described by the following chemical reaction equation:

CuO + H2 = Cu + H2O;

Cupric oxide reacts with hydrogen in equal (equivalent) molar amounts. In the course of the reaction, the same equal chemical amounts of copper and water are synthesized.

Let’s calculate the chemical amount of copper oxide.

To do this, divide the weight of the oxide by the weight of 1 mole of oxide.

M CuO = 64 + 16 = 80 grams / mol;

N CuO = 40/80 = 0.5 mol;

Thus, it is possible to carry out the reduction of 0.5 mol of copper oxide and obtain 0.5 mol of copper.

The same amount of water will be synthesized. Let’s calculate its weight.

M H2O = 2 + 16 = 18 grams / mol;

m H2O = 0.5 x 18 = 9 grams;