Copper oxide is reduced with hydrogen. Determine the mass of reduced copper if 0.2 g of hydrogen was used for reduction.

Copper oxide is reduced with hydrogen gas. This synthesizes metallic copper and water. This reaction is described by the following equation:

CuO + H2 = Cu + H2O;

Copper oxide reacts with hydrogen in equal molar amounts. At the same time, the same equal amounts of copper and water are synthesized.

Let’s determine the chemical amount of hydrogen gas.

For this purpose, we divide its weight by the weight of 1 mole of gas.

M H2 = 2 grams / mol;

N H2 = 0.2 / 2 = 0.1 mol;

Thus, it is necessary to reduce 0.1 mol of copper oxide and synthesize 0.1 mol of copper.

Its weight will be:

M Cu = 64 grams / mol;

m Cu = 64 x 0.1 = 6.4 grams;