Copper rheotan wire, length of which is 20 m, has a resistance of 5.8 ohms, which is the cross-sectional area of this wire.

Initial data: l (length of copper rheotan wire) = 20 m; R (wire resistance) = 5.8 ohms.

Reference data: ρ (specific electrical resistance of copper) = 0.017 Ohm * mm2 / m.

The cross-sectional area of the copper rheotan wire is determined from the formula: R = ρ * l / S, whence S = ρ * l / R.

Calculation: S = 0.017 * 20 / 5.8 = 0.059 mm2.

Answer: The cross-sectional area of the wire is 0.059 mm2.



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