Copper, silver, aluminum are in the alloy in a ratio of 1: 2: 3. Find the mass of aluminum if the mass of the alloy is 180g.

We solve the problem by drawing up an equation.

Let x (z) be the mass of one part.

Then 1x (g) was in a copper alloy, 2x (g) was in a silver alloy, 3x (g) was in an aluminum alloy.

1x + 2x + 3x (g) – there were all metals, and this is 180g.

The equation:

1x + 2x + 3x = 180;

6x = 180;

x = 180: 6;

x = 30.

1) 3 * 30 = 90 (g) – it was in the aluminum alloy.

Answer: 90g.