Copper sulfate II and lead chloride II in ionic form.

1. Let’s write the reaction equation in molecular form:

CuSO4 + PbCl2 = PbSO4 ↓ + CuCl2;

2.Taking into account that the precipitate does not conditionally decompose into ions, we write down the complete ionic equation:

Cu²⁺ + SO₄^2- + Pb²⁺ + 2Cl^– = PbSO₄↓ + Cu²⁺ + 2Cl^–;

3.reducting identical ions on both sides of the equation, we obtain an abbreviated ionic reaction equation:

Pb²⁺ + SO₄² = PbSO₄↓.