Copper sulfate m = 50g was dissolved in water m-350g. What is the mass fraction of copper sulfate 2 in the solution.

Given
m (CuSO4 * 5H2O) = 50g
m (H20) = 350 g
ω (CuSO4) -?
Decision
1. find the mass fraction of copper sulfate 2 IN SALT
ω (CuSO4 in salt) = M (CuSO4) / M (CuSO4 * 5H2O)
ω (CuSO4 in salt) = 160/250 = 0.64
2. find the mass of copper sulfate 2
m (CuSO4) = m (CuSO4 * 5H2O) * ω (CuSO4 in salt)
m (CuSO4) = 50 * 0.64 = 32 g
3.Find the mass fraction of COPPER 2 sulfate IN SOLUTION
ω (CuSO4) = m (CuSO4) / m (solution)
m (solution) = m (H20) + m (CuSO4 * 5H2O)
ω (CuSO4) = 32 / (350 + 50) = 0.08
Answer: the mass fraction of copper sulfate 2 in the solution is 8%