Copper sulfate weighing 100 g was dissolved in water and electrolysis was carried out until the solution became

Copper sulfate weighing 100 g was dissolved in water and electrolysis was carried out until the solution became discolored. Is the volume of collected gas equal?

1. Let’s write down the equation of electrolysis of a solution of copper sulfate:

K (-): Cu ^ + 2 + 2 e- → Cu ^ 0;

A (+): 2H2O – 4 e- → O2 + 4H ^ +;

2CuSO4 + 2H2O (electrolysis) → 2Cu + O2 ↑ + 2H2SO4;

2.determine the mass fraction of copper sulfate in the formula of copper sulfate:

w (CuSO4) = Mr (CuSO4): Mr (CuSO4 * 5H2O);

Mr (CuSO4) = 64 + 32 + 4 * 16 = 160;

Mr (CuSO4 * 5H2O) = 64 + 32 + 4 * 16 + 5 * 18 = 250;

w (CuSO4) = 160: 250 = 0.64;

3.Calculate the mass of copper sulfate in a portion of copper sulfate:

m (CuSO4) = w (CuSO4) * m (CuSO4 * 5H2O) = 0.64 * 100 = 64 g;

4.Calculate the chemical amount of copper sulfate:

n (CuSO4) = m (CuSO4): M (CuSO4) = 64: 160 = 0.4 mol;

5. find the amount of released oxygen:

n (O2) = n (CuSO4): 2 = 0.4: 2 = 0.2 mol;

6.Calculate the volume of oxygen:

V (O2) = n (O2) * Vm = 0.2 * 22.4 = 4.48 liters.

Answer: 4.48 liters.