Copper sulfate weighing 25 g was dissolved in water with a mass of 175 g, the mass fraction of copper

Copper sulfate weighing 25 g was dissolved in water with a mass of 175 g, the mass fraction of copper sulfate in the resulting solution is equal to.

1. Let’s find the chemical amount of copper sulfate:

n (CuSO4 * 5H2O) = m (CuSO4 * 5H2O): M (CuSO4 * 5H2O);

M (CuSO4 * 5H2O) = 64 + 32 + 4 * 16 + 10 + 5 * 16 = 250 g / mol;

n (CuSO4 * 5H2O) = 0.1 mol;

2.determine the mass of copper sulfate:

n (CuSO4) = n (CuSO4 * 5H2O) = 0.1 mol;

m (CuSO4) = n (CuSO4) * M (CuSO4);

M (CuSO4) = 64 + 32 + 4 * 16 = 160 g / mol;

m (CuSO4) = 0.1 * 160 = 16 g;

3.Calculate the mass of the resulting solution:

m (solution) = m (CuSO4 * 5H2O) + m (H2O) = 25 + 175 = 200 g;

4.Set the mass fraction of sulfate:

w (CuSO4) = m (CuSO4): m (solution) = 16: 200 = 0.08 or 8%.

Answer: 8%.